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Tertitten #1
Member since Mar 2009 · 1 post
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Subject: Checking if user gets disconnected
Hi, I would like to add the status of a user when it changes to the chat window TextBox, however I can't really figure out how to do it...

I tought something like this would do the trick:
        public void PresenceChanged(agsXMPP.protocol.client.Presence state)
        {
            if (state.Type == PresenceType.unavailable)
                rtfChat.AppendText("User offline");
        }
But that did nothing, can someone please help out ?
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Alex #2
Member since Feb 2003 · 4307 posts · Location: Germany
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this looks correct.
can you post the code which calls the PresenceChanged function?

Alex
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[gja] #3
Member since Jul 2009 · 19 posts
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Subject: same problem with this one
how will i know if i am disconnected to the openfire server?..and notify me if i am disconnected..pls help me how to do this.


thanks,
glen
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Alex #4
Member since Feb 2003 · 4307 posts · Location: Germany
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when you get disconnected the you should get the OnClose or one of the OnError... events.

Alex
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[gja] #5
Member since Jul 2009 · 19 posts
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Subject: Check online user
hello guys,

i know this is very basic to you.but for me that just started the xmpp.i just a little confused on how to do this..

i have button named 'btnCheck' and a textbox named 'txtaddress'.i inputed the textbox an adress(e.g 1234@domain) and after clicking btncheck.this will check if 1234@domain address is online/offline..how will i do this..can u give me simple code snippet?..

many thanks..
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Alex #6
Member since Feb 2003 · 4307 posts · Location: Germany
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pleasy study our MiniClient example. There is all you need.

If you want to learn XMPP is suggest XMPP: The Definitive Guide

Alex
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Forum: agsXMPP RSS