Sending a message - easy question, surely!

owen

2006-11-30, 12:15 #1

Member since Nov 2006 · 21 posts · Location: UK
Group memberships: Members

Show profile ·

Link to this post

Subject: Sending a message - easy question, surely!

Hi.

I'm a newbie so please excuse the dumbness of this question. I've already searched this Forum and couldn't find the answer. I am trying to create a very basic VB.NET desktop app to demo the ability to send a message from one Google chat user to another. I can connect, authenticate, send my presence, and that works fine.

What I am struggling with, is the basic task of sending the message.   The problem being, it just doesn't get there. But I don't get an error, either.

At this point I am definately connected and authenticated, plus my status shows "Online" at TheRecipient's desktop.

But TheRecipent simply does not recieve the message. However, my presence shows up in their google IM client correctly. I think I'm missing something simple here, but I cannot see what it is.

Here's the relevant code; a "Send" button and a "Login" button:
_____________

Private Sub SendButton_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles SendButton.Click
      Dim msg As agsXMPP.protocol.client.Message = New agsXMPP.protocol.client.Message
      msg.Type = MessageType.normal
      msg.Subject = "test subject"
      msg.To = New Jid("TheRecipient", "gmail.com", "owentest")
      msg.Body = "If you can read this, it has worked."
      msg.From = New Jid("MySelf", "gmail.com", "owentest")
      XMPP.Send(msg) ' <---- where does the message go? TheRecipient doesn't get it!?!?!
    End Sub

    Private Sub LoginButton_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles LoginButton.Click
      With XMPP
      Dim cb As New agsXMPP.MessageCB(AddressOf MessageCallback)

      Dim MyJid As New Jid("MySelf", "gmail.com", "owentest")
      .MesagageGrabber.Add(MyJid, cb, Nothing)

      Dim pcb As New agsXMPP.PresenceCB(AddressOf PresenceCallback)
      .PresenceGrabber.Add(MyJid, pcb, Nothing)

      .Server = "gmail.com"
      .ConnectServer = "talk.google.com"
      .Username = "MySelf"
      .Password = "MyPassword"
      .Port = "5222"
      .UseSSL = False
      .Status = "Online"
      .Priority = 5
      .AutoResolveConnectServer = True

      .AutoRoster = True

      .RegisterAccount = False
      .Show = agsXMPP.protocol.client.ShowType.chat
      .Open()

      End With
    End Sub

    Private Sub PresenceCallback(ByVal sender As Object, ByVal pres As agsXMPP.protocol.client.Presence, ByVal data As Object)
      Label1.Text = pres.Nickname.ToString & " status = " & pres.Status
    End Sub

    Private Sub MessageCallback(ByVal sender As Object, ByVal msg As agsXMPP.protocol.client.Message, ByVal data As Object)
      Label1.Text = msg.From.User & " said: " & msg.Body
    End Sub
___________

Alex

2006-11-30, 12:33 #2

Member since Feb 2003 · 4449 posts · Location: Germany
Group memberships: Administrators, Members

Show profile ·

Link to this post

Hello owen,

Quote by owen:
Private Sub SendButton_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles SendButton.Click
      Dim msg As agsXMPP.protocol.client.Message = New agsXMPP.protocol.client.Message
      msg.Type = MessageType.normal
      msg.Subject = "test subject"
      msg.To = New Jid("TheRecipient", "gmail.com", "owentest")
      msg.Body = "If you can read this, it has worked."
      msg.From = New Jid("MySelf", "gmail.com", "owentest")
      XMPP.Send(msg) ' <---- where does the message go? TheRecipient doesn't get it!?!?!
    End Sub

msg.From is optional, i wouldn't add it. The server does this on behalf of you. If you add it then you must be sure that it's 100% correct. GoogleTalk normally assigns a resource to your connection, so it will be different than the one you specified when connecting.

Are you sure that msg.To is correct? Especially the resource? If not then try to send the message to a bare Jid (without resource).

Google drops messages if both contacts are not subscribed to each other. So make sure the subscription is OK on both sites (subscription='both').

Alex

2006-11-30, 12:37 #3

Member since Feb 2003 · 4449 posts · Location: Germany
Group memberships: Administrators, Members

Show profile ·

Link to this post

hm, and i never tried to send a message of type = normal to GTalk. So you could also try the chat type.
And the subject is not needed for chat messages.

Alex

owen

2006-11-30, 12:58 #4

Member since Nov 2006 · 21 posts · Location: UK
Group memberships: Members

Show profile ·

Link to this post

In reply to post #2

Excellent thank you, Alex.

Simplifying the Jid and removing the .From property, seemed to do the trick.

Works nicely.

Alex

2006-11-30, 18:11 #5

Member since Feb 2003 · 4449 posts · Location: Germany
Group memberships: Administrators, Members

Show profile ·

Link to this post

ok cool.

XMPP is different than the other IM systems here. Because you can login to a xmpp server with the same user id unlimited times. Only the resource has to be different.

That means

you can send the message to the full Jid (with resource) of a contact then only this connection receives it

or to the bare Jid then the server decides according to the routing rules defined in the XMPP core which connection gets this message.

Alex