Page: 1 
softyboy
Show profile
Link to this post
Subject: Conference invitation Accept
Hello,
How can accept and decline conference invitation. with mucManager classs.
How can accept and decline conference invitation. with mucManager classs.
- If you want to accept the invitation then just join the room.
- to decline the invite use the Decline() member of the MucManager
Alex
tanks alex,
alex i would like to know which event will be generate when some body send me invitation for conference.
( i have done send invitaion to user )
alex i would like to know which event will be generate when some body send me invitation for conference.
( i have done send invitaion to user )
Because a invite is sent inside a message stanza you get an OnMessage event. In this event you have to check if it is a normal message or a invite or something else.
Thanks alex for great support.
i have get he xml but how can get the invitaion jid from xml .
i have get he xml but how can get the invitaion jid from xml .
i don't understand your question.
From which event, or which xml you want to get a Jid?
And which Jid you you want?
The Jid of the person which invites you, or the Jid of the chatroom to which you get the invite?
From which event, or which xml you want to get a Jid?
And which Jid you you want?
The Jid of the person which invites you, or the Jid of the chatroom to which you get the invite?
Software Developer
AG-Software
AG-Software
ya jaberer,
jid of the person which invites me, and jid of the chatroom which send me the invitation.
jid of the person which invites me, and jid of the chatroom which send me the invitation.
This post was edited on 2006-09-14, 09:46 by
get the invite object of rfom the message object and use the properties of the invite object.
Software Developer
AG-Software
AG-Software
hello jabberer,
i have write these code
Private Sub m_XMPPConnection_OnMessage(ByVal sender As Object, ByVal msg As agsXMPP.protocol.client.Message) Handles
Dim inv As New x.muc.Invite=ctype(msg,x.muc.invite)
end sub
but it's generate type conversion error,
i mean to say how can get the invite object from message object
i have write these code
Private Sub m_XMPPConnection_OnMessage(ByVal sender As Object, ByVal msg As agsXMPP.protocol.client.Message) Handles
Dim inv As New x.muc.Invite=ctype(msg,x.muc.invite)
end sub
but it's generate type conversion error,
i mean to say how can get the invite object from message object
sure, you can't cast Message to Invite.
Invite is a childnode of msg, so use:
Invite is a childnode of msg, so use:
- msg.SelectSingleElement(typeof(Invite));
Software Developer
AG-Software
AG-Software
thanks jabberer,
but still i have facing problem.
in OnMessage() event------
Dim m_Invite As Invite
m_Invite = msg.SelectSingleElement(gettype(invite))-- It return nothing when user send the conference request.
MsgBox("Invite from " + m_Invite.From.User)
MsgBox("Invite Id " + m_Invite.Id.ToString)
but still i have facing problem.
in OnMessage() event------
Dim m_Invite As Invite
m_Invite = msg.SelectSingleElement(gettype(invite))-- It return nothing when user send the conference request.
MsgBox("Invite from " + m_Invite.From.User)
MsgBox("Invite Id " + m_Invite.Id.ToString)
Please post the XML of your message and your invite object.
thanks Alex,
Sub m_XMPPConnection_OnMessage(ByVal sender As Object, ByVal msg As agsXMPP.protocol.client.Message) Handles m_XMPPConnection.OnMessage
Dim m_Invite As Invite
m_Invite = msg.SelectSingleElement("invite") - return nothing
If InvokeRequired Then
BeginInvoke(CType(AddressOf m_XMPPConnection_OnMessage, agsXMPP.XmppClientConnection.MessageHandler), New Object() {sender, msg})
Return
End If
End Sub
in OnReadXml enevt get xml
Private Sub m_XMPPConnection_OnReadXml(ByVal sender As Object, ByVal xml As String) Handles m_XMPPConnection.OnReadXml
<message xmlns="jabber:client" from="parwej_5ip@conference.java" to="me@java">
<x xmlns="http://jabber.org./protocol/muc#user">
<invite from="parwej@java">
<reason>Please join me in a conference. </reason>
</invite>
</x>
<x xmlns="jabber:x:conference" jid="parwej_5i9@conference.java" />
</message>
End Sub
Sub m_XMPPConnection_OnMessage(ByVal sender As Object, ByVal msg As agsXMPP.protocol.client.Message) Handles m_XMPPConnection.OnMessage
Dim m_Invite As Invite
m_Invite = msg.SelectSingleElement("invite") - return nothing
If InvokeRequired Then
BeginInvoke(CType(AddressOf m_XMPPConnection_OnMessage, agsXMPP.XmppClientConnection.MessageHandler), New Object() {sender, msg})
Return
End If
End Sub
in OnReadXml enevt get xml
Private Sub m_XMPPConnection_OnReadXml(ByVal sender As Object, ByVal xml As String) Handles m_XMPPConnection.OnReadXml
<message xmlns="jabber:client" from="parwej_5ip@conference.java" to="me@java">
<x xmlns="http://jabber.org./protocol/muc#user">
<invite from="parwej@java">
<reason>Please join me in a conference. </reason>
</invite>
</x>
<x xmlns="jabber:x:conference" jid="parwej_5i9@conference.java" />
</message>
End Sub
OK i see,
you have to get the agsXMPP.protocol.x.muc.User object first and then the Invite Object from the User object.
you have to get the agsXMPP.protocol.x.muc.User object first and then the Invite Object from the User object.
Software Developer
AG-Software
AG-Software
you mean,
Dim User As agsXMPP.protocol.x.muc.User
User.Invite = msg.SelectSingleElement(GetType(Invite))
Dim m_Invite As Invite = User.Invite
but it not work , if any pls tell me
Dim User As agsXMPP.protocol.x.muc.User
User.Invite = msg.SelectSingleElement(GetType(Invite))
Dim m_Invite As Invite = User.Invite
but it not work , if any pls tell me
Forum: agsXMPP 